ajax - $.post into a php class function -
i want make live username check , want use php function.
--> <?php require '../../core/init.php'; ?> <!doctype html> <html lang="de"> <head> <meta charset="utf-8"> <title>köppcms - registrieren</title> <link rel="stylesheet" href="../../../css/style.css"> <script type="text/javascript" src="../../../js/jquery.js"></script> <script type="text/javascript" src="../../../js/footer.js"></script> <script type="text/javascript"> $(document).ready(function() { $("#username").keyup(function (e) { //removes spaces username $(this).val($(this).val().replace(/\s/g, '')); var username = $(this).val(); //get string typed user $.post('users.php', {'username':username}, function(data) { //make ajax call users.php $("#user-result").html(data); //dump data received php page }); }); }); </script> </head> init.php:
<?php session_start(); require 'database/connect.php'; require 'classes/users.php'; require 'classes/general.php'; $users = new users($db); $general = new general(); $errors = array(); ?> so how can call check_username function , send values it? hope understand question, because english isn't good.
i'd tried in users.php:
<?php $users = new users($db); echo $users->check_username($_post['username']); class users{ private $db; public function __construct($database) { $this->db = $database; } public function check_username($data) { return $data+1; } function func1($data){ return $data+1; } } get error:
notice: undefined variable: db in c:\xampp\htdocs\kcms\system\cms\user\users.php on line 2 
your php script should like:
<?php require('init.php'); // contains $users = new users($db); echo $users->check_username($_post['username']); for using return value in javascript, see
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