arrays - C++ Enum values from string input -

been @ 1 while now, appreciate help.

i'm create , object card enum values rank , suit based on string input. string in format of '2c, ad' etc. 2 clubs , ace diamonds respectively.

i tried using linear search function found elsewhere on stackoverflow, it's in there returns -1 because doesn't seem getting right type of input.

i've been able convert other way using char * array, can't life of me opposite way around. see below implementation:

card.h

#ifndef _card_h #define _card_h  #include <string> #include <iostream>  using namespace std;   enum rank{  two, three, four, five, six, seven,             eight, nine, ten, jack, queen, king, ace};   enum suit{  clubs, diamonds, hearts, spades};  //character sets used convert enums strings static const char * rankstrings[] = { "2", "3", "4", "5", "6", "7", "8", "9", "t", "j", "q", "k", "a",}; static const char * suitstrings[] = { "c", "d", "h", "s" };  class card {  public:      ///constructors , destructors     card();     ~card();      ///accessors     rank getrank();     suit getsuit();     string getsuitstring();     string tostring(); ///no longer used, left testing     int linearsearch(const char**, const char*, int);      ///mutators     card(rank rank, suit suit);     card(string cardstr);       ///operators     bool operator()(card*, card*);     friend ostream& operator<<(ostream&, card&);  private:     suit suit;     rank rank; };  #endif // _random_h 

card.cpp

#include "card.h" #include <string> #include <stdlib.h> #include <cstring> #include <iostream> #include <sstream> using namespace std;  /**constructors*/ ///noarg constructor sets default card values card::card(){     suit = clubs;     rank = two; }  card::~card(){} //destructor  /**accessors*/ rank card::getrank(void){     return rank; }  suit card::getsuit(void){     return suit; }  string card::getsuitstring(){     return suitstrings[suit]; }  /**from tutorial, used during testing has been reimplemented  * overloaded operator<< below  */ string card::tostring(){      string cardvalues;      cardvalues += rankstrings[rank];     cardvalues += suitstrings[suit];      return cardvalues; }  /**mutators*/ ///create new card given rank , suit card::card(rank cardrank, suit cardsuit){     rank = cardrank;     suit = cardsuit; }  int card::linearsearch (const char **array, const char *searchkey, int arraysize) {     (int = 0; < arraysize; ++i) {         if (strcmp(array[i], searchkey) == 0)             return i;     }      // didn't find searchkey in array     return -1; }  ///sets card rank , suit based on string input card::card(string cardstr){     stringstream ss;     string rankstr;      char *c = &cardstr.at(0);     cout << *c << endl; //this prints correct value doesnt work in method below      int index = linearsearch(rankstrings, c, 13);     cout << index << endl;   }    /**operators*/ ///functor compare 2 cards value bool card::operator()(card* card1, card* card2){     return card1->getrank() > card2->getrank(); }  ///puts string representation of input card on output stream ostream& operator<<(ostream& out, card& card){     out << rankstrings[card.rank] << suitstrings[card.suit];     return out; } 

the problem taking address of '2' in "2c" , using if complete c string. when use strcmp in linearsearch trying match whole string ("2c") , fails.

one way around change suitstrings or rankstrings char instead of char *, involve changing other methods well.

another way copy char working seperate 1 character string strcmp work. should it:

char rankstr[2]; rankstr[0] = cardstr[0]; rankstr[1] = '\0'; // null terminated.  int index = linearsearch(rankstrings, rankstr, 13); 

yet way change linearsearch @ first character of both strings.