Semi-random numbers generation in C++ -

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• how select value list non-uniform probabilities? 4 answers

suppose have set of numbers x = {0, 0, 0, 0, 1, 2, 2, 3}. there way me use rand() print out random numbers list proportion of generated numbers on time original proportion of numbers in set? in other words, proportion of zeros 0.5, ones 0.125, twos 0.25, , threes 0.125.

you can specifying frequencies:

#include <iostream> #include <random>  int main() {     using namespace std;     mt19937_64 engine;      discrete_distribution<int> numbers{4, 1, 2, 1};      cout << numbers(engine) << endl; }