ksh: zero divisor error when declaring a variable -

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update: weird. looked further, , realized there 2 *ksh packages in server:

pdksh-5.2.14-37.el5_8.1.x86_64 mksh-39-7.el6_4.1.x86_64

and mksh set in /etc/alternatives:

lrwxrwxrwx 1 root root 9 apr 23 10:39 /etc/alternatives/ksh -> /bin/mksh

i pointed /bin/pdksh, tried script again, , worked.

to replicate issue, changed /bin/mksh, time, script worked without error. in short, not replicate issue anymore. weird.

i'm looking further. thanks.

given korn shell script:

#!/bin/ksh  u=$1

with $1 passed abc/s0mething, how can work around error?

ksh: abc/s0mething 0 divisor.

ksh version:

@(#)mirbsd ksh r39 2009/08/01

thanks.

it's weird, if asking workaround, can be

u=`printf '%q' $1`

however, not able replicate problem on system understand it... if doesn't work, shall remove answer.


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