bash - How to pass filename through variable to be read it by awk -

good day,

i wondering how pass filename awk variable, in order awk read it.

so far have done:

echo    file1   >  aenumerar echo    file2   >> aenumerar echo    file3   >> aenumerar  ae=`grep -c '' aenumerar` r=1 while [ $r -le $ae ];     lista=`awk "nr==$r {print $0}" aenumerar`     aelist=`grep -c '' $lista`     s=1     while [ $s -le $aelist ];         word=`awk -v var=$s 'nr==var {print $1}' $lista`         echo $word     let "s = s + 1"     done let "r = r + 1" done 

thanks in advance clue or other simple way bash command line

instead of:

awk "nr==$r {print $0}" aenumerar 

you need use:

awk -v r="$r" 'nr==r' aenumerar