Case insensitivity in "if" statement (Python) -

this question has answer here:

• how test 1 variable against multiple values? 16 answers
• why `a == b or c or d` evaluate true? [duplicate] 1 answer

i working on project @ 1 point ask user yes/no question. use code handle such questions:

def yn():     global finalchoice     choice=str(raw_input("y/n: "))     if choice == "y":         finalchoice="true"     elif choice == "y":         finalchoice="true"     elif choice == "n":         finalchoice="false"     elif choice == "n":         finalchoice="false"     else:         yn()     pass 

but seems quite inefficient, have check both "y" , "y" or "n" , "n" separately. i've tried:

if choice == "y" or "y":     finalchoice="true" 

unfortunately, ignore 'else' command , pass whatever give it.

any tips?

if choice == "y" or "y": not right! evaluate true.

it (choice == "y") or ("y"). , latter true because non empty string in python logically evaluates boolean true.

you should doing:

if choice in ["y","y"]: 

or,

if choice == "y" or choice == "y": 

or can use:

if choice.lower() == "y":     finalchoice="true"